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2x^2-7x-130=0
a = 2; b = -7; c = -130;
Δ = b2-4ac
Δ = -72-4·2·(-130)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-33}{2*2}=\frac{-26}{4} =-6+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+33}{2*2}=\frac{40}{4} =10 $
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